The length of a rectangle is three times its breadth.The perimeter of the rectangle is equal to that of a square whose are a is 625cm^2.Find the area of the rectangle.
Please explain
Please answer it correctly
I will mark you as brainlist
Please answer it very fast
harshit355:
class10th
Answers
Answered by
39
Here is your solution
Let,
Breadth = x
Then Length = 3 times of breadth.
lenght = 3x
Given that
The perimeter of the rectangle =area of square = 625
perimeter of rectangle =2 (l+b)
625=2 (3x+x)
625/2=4x
625/2×4 = x
78.125 = x
Hence
Area of rectangle = length × breadth
Area of rectangle = 3X × x
Area of rectangle = 3×78.125 × 78.625
Area of rectangle =18427.7 cm^2
Let,
Breadth = x
Then Length = 3 times of breadth.
lenght = 3x
Given that
The perimeter of the rectangle =area of square = 625
perimeter of rectangle =2 (l+b)
625=2 (3x+x)
625/2=4x
625/2×4 = x
78.125 = x
Hence
Area of rectangle = length × breadth
Area of rectangle = 3X × x
Area of rectangle = 3×78.125 × 78.625
Area of rectangle =18427.7 cm^2
Answered by
6
let the breadth of the rectangle=x then the length of the rectangle=3x ∴according to problem 2(3x+x)=88 ⇒2*4x=88 ⇒8x=88⇒x=11 hence,the breadth=11cm the length=3*11cm=33cm
Similar questions