Question

The length of a rectangle is three times its width. Find the length and width of the space whose circumference is 300 m.​

Answer 1

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REF.Image

Given [l=3b]

In ΔABC

AC

2

=b

2

+l

2

360=10b

2

b

2

=36

[b= 6 cm] & [l= 18 cm]

Perimeter of rectangle = 2[l+b]

=2[6+18]

=2×24

perimeter = 48 cm

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