Question

The length of a rectangle is three times its width. It the perimeter of the rectangle is 96m, find the
length and breadth of the rectangle​

Answer 1

Given :

• The length of a rectangle is three times its width.
• If the perimeter of the rectangle is 96m.

To Find :

• Length and Breadth

Solution :

• Let Length be 3x cm
• And Breadth be x cm

Perimeter = 2 (L + B)

➛ 96 = 2 (3x + x)

➛ 96/2 = 3x + x

➛ 48 = 4x

➛ x = 48/4

➛ x = 12cm

Now, Length and Breadth

➛ Length = 3x

➛ Length = 3 × 12

➛ Length = 36cm

➛ Breadth = 12cm

Verification :

Perimeter = 2 (L + B)

➛ 96 = 2 (12 + 36)

➛ 96 = 2 × 48

➛ 96 = 96

Therefore, Required Length and breadth of The rectangle is 36cm and 12cm.

_____________

Answer 2

$\Large\pink\pmb{Answer:-}$

The perimeter of the rectangle is given as 96 m.

Let, the width of the rectangle = x

According, to the given condition,

Length = 3x

Width = x

As we know,

Perimeter of a rectangle = 2 (L +B)

Then,

➪96 = 2( 3x + x)

➪ 96 = 2(4x)

➪ 96 = 8x

➪ 96/8 = x

➪ 12 = x

The value of x = 12 m.

ie, the width of the rectangle = 12 m

Then, length = 3x

➪ 3 × 12

➪ 36 m

•°• Length = 36 m and Breadth = 12 m.

$\Large\red\pmb{Verification:-}$

• Perimeter = 2 (Length + Breadth)

• 96 = 2(L+B)

On substituting the values,

• 96 = 2 ( 36 + 12)

• 96 = 2 ( 48)

• 96 = 96

• LHS = RHS

Hence verified!!

Happy Learning!!