Question

the length of a rectangle is three times of it's width if the length of the diongal is 8/10 m then the perimeter of the rectangle is ​

Answer 1

Answer:

Let the breadth be x cm, then , length = 3x cm . ∴diagonal =√(3x)2+x2cm=x√10cm. Thus ,x√10=8√10⇒=8...

Answer 2

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The length of a rectangle is 3 times of its width

The length of the diagonal is 8 square root 10

To Find :

Find the perimeter of the rectangle

Solution:

Let the width of rectangle be x

We are given that length of rectangle is 3 times of its width

Length of rectangle = 3x

Diagonal² =Length² +Width²

We are given that length of diagonal is 8√10

(8√10)² =(3x)² +x²

6400=9x² +x²

6400=10x²

640=x²

√640 =x

25.29=x

Length of rectangle = 3x =3(25.29)= 75.87 m

Width of rectangle = 25.29 m

Perimeter of rectangle =2(l+b)=2(75.87+25.29)= 202.32 m

Hence The perimeter of rectangle is 202.32 m