The length of a rectangle is twice as long as
the side of a square. The side of a square is
4 cm longer than the width of the same
rectangle. If their areas are equal, find their
dimensions.
[4 Marks]
Answers
Answer:
Length of rectangle = 16 cm
Width of rectangle = 4 cm
Side of square = 8 cm
Step-by-step explanation:
Let the width of the rectangle be x cm.
A/q, Side of the square = (x + 4) cm
Also, Length of rectangle = 2(Side of square)
On further solving, we get
→ Length = 2(x + 4)
Now,
A.T.Q.,
Area of square = Area of rectangle
→ (Side of square)² = Length of rectangle × Width of rectangle
Putting the known values, we get
→ (x + 4)² = 2(x + 4) × x
→ x² + 16 + 8x = 2x(x + 4)
→ x² + 16 + 8x = 2x² + 8x
→ 2x² - x² + 8x - 8x - 16 = 0
→ x² - 16 = 0
→ x² = 16
→ x = √16
→ x = ± 4
Dimensions can't be negative.
Hence, x = 4 cm
________________________
• Length of rectangle = 2(x + 4)
→ 2(4 + 4)
→ 2(8)
→ 16 cm
_________________________
• Width of rectangle = x
→ 4 cm
_________________________
• Side of square = (x + 4)
→ (4 + 4)
→ 8 cm
Given:
• The length of a rectangle is twice as long as the side of a square.
• The side of a square is 4 cm longer than the width of the same.
rectangle.
Find:
Find their dimensions.
Calculations:
Let y cm be the width of the rectangle.
Let (y + 4) cm be side of the square.
Formula:
Adding values to the above formulas:
Dimensions shouldn't be negative, so the value of y = 4 m.