Question

the length of a rectangle is twice it's breadth .If the peremiter is 72 meter , find the length and breadth of the the rectangle ​

Answer 1

Answer:

let the breadth of the rectangle is x m

so, length= 2x m

perimeter=2(length+breadth)=72

=> 2(2x+x)=72

=> 2.3x=72

=> 6x=72

=> x=72/6=12

so,breadth of the rectangle is 12 m

and length =2×12m=24 m

Answer 2

$\Huge\rm\orange{answeR}$

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$\bf{{\underline{Given}}:}$

• The Length of a rectangle is twice it's breadth
• Perimeter of the rectangle is 72m

$\bf{{\underline{To~find}}:}$

• The Length and breadth of the rectangle

$\bf{{\underline{Solution}}:}$

$\sf Length = 2 \times breadth \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf Let \: length \: and \: breadth \: be \: \: x\: \: and \: \: y \\ \: \: \: \: \: \: \: \: \: \: \sf \implies x = 2y \\ \\ \sf Perimeter \: of \: a \: rectangle = 2(l + b) ~~~~~~~~~~~~~~~~~~ \: \: \: \: \: \: \: \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \implies \sf 2(x + y) = 72 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \implies \sf 2(2y + y) = 72 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \implies \sf 2(3y) = 72 \\ \: \: \: \: \: \: \: \: \: \: \: \: \implies \sf 6y = 72 \\ \: \: \: \: \: \: \: \: \: \: \: \implies \sf y = \frac{72}{6} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \implies \sf y = \orange{ \underline{ \boxed{ \bf 12}}}$

$\bf\therefore{{\underline{Required~answer}}:}$

• $\sf{Length,~x=2y=2×12=\orange{\underline{\boxed{\bf 24m}}}}$
• $\sf{Breadth,~y=\orange{\underline{\boxed{\bf 12m}}}}$

$\bf{{\underline{Verification}}:}$

$\sf Perimeter \: of \: a \:rectangle = 2(l + b) \: \: \: \: \: \: \: ~~~~~~~~~\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf = 2(24 + 12) \\ \sf = 2(36) \: \: \: \: \: \: \: \: \: \: \\ \sf = \orange{ \underline{ \boxed{ \bf 72m}}} \: \: \: \: \: \: \: \:$