Question

the length of a rectangle is twice it's breadth.the perimeter of the rectangle is 120m.find it's area
Please tell ​

Answer 1

Answer:

Area of the rectangle is 800 m²

Step-by-step explanation:

Solution :

Let,

The Breadth of the rectangle (b) = a

The Length of the rectangle (l) = 2a

We know that,

★ The Perimeter of the rectangle = 2 (l + b)

★ According to the Question :

The Perimeter of the rectangle = 120 m

So,

⇒ 2 (a + 2a) = 120

⇒ 2 (3a ) = 120

⇒ 6a = 120

⇒ a = 120 / 6

⇒ a = 20

The Breadth of the rectangle = 20 m

The Length of the rectangle = 2a

⇒ 2 (20)

⇒ 40

The Length of the rectangle = 40 m

★ Area of the rectangle = (l × b)

⇒ 40 × 20

⇒ 800

Area of the rectangle = 800 m²

Therefore,

Area of the rectangle is 800 m²

Answer 2

Given :

• Length of a rectangle is twice it's breadth.
• The perimeter of the rectangle = 120 m

To find :

• The area of the rectangle.

Solution :

Here it is said that the length of the rectangle is twice the breadth. So we will assume that the breadth be x. Then, the length will be 2x. Now we can find the value of x by the following formula:-

• Perimeter = 2(length + breadth)

→ 120 = 4x + 2x

→ 120 = 6x

→ 120/6 = x

→ 20 = x

→ x = 20

•°• the length = 2x = 40 m

•°• the breadth = x = 20 m

Now when we have got the length and breadth of the rectangle we can find the area by the following formula:-

• Area = length × breadth

→ Area = 40 × 20

→ Area = 800 m²

Answer :

• The area of the rectangle = 800 m²