Question

the length of a rectangle is twice it's width.The perimeter is 30.Findit's dimension using simultaneous equations

Answer 1

Answer:

Step-by-step explanation:

Let the length and width of a rectangle is respectively x and y.

x=2y

x+y=30

2y+y=30

3y=30

y=10

x=2y

x=2×10

x=20

Therefore length and width are 20 and 10 respectively

Answer 2

Answer:

Length = 10 cm & Breadth = 5 cm

Step-by-step explanation:

Let the length of rectangle be l & breadth be b.

⇒ l = 2b

Perimeter of rectangle = 2(l + b) = 30

⇒ 2(2b + b) = 30

⇒ 2(3b) = 30

⇒ 6b = 30

⇒ b = 5

⇒ l = 2(5) = 10

∴ Length = 10 cm & Breadth = 5 cm