Question

the length of a rectangle is twice its breadth if its perimeter is 60 cm find the length and the breadth of the rectangle​

Answer 1

let the breadth of the rectangle be at and the length be 2x.

perimeter=2(length+breadth)

=}60=2(X+2x)

=}60=2×3x

=}60=6x

=}6x=60

=}X=60/6=10

hence, breadth=X=10

length=2x=10×2=20

Hope it's helpful and if it is please mark as brainliest

Answer 2

$\mathfrak{\huge{\green{\underline{Given:-}}}}$

Perimeter of the rectangle = 60 cm

Length of the rectangle = Twice it's breadth

$\mathfrak{\huge{\green{\underline{To \: Find:-}}}}$

Length of the rectangle.

Breadth of the rectangle.

$\mathfrak{\huge{\green{\underline{Solution:-}}}}$

Perimeter of the rectangle = 2 (Length + Breadth)

Let the breadth be x and length be 2x

Then,

Perimeter of the rectangle = $\sf 2(2x+x)=60$

$\implies \sf 2 \times 3x=60$

$\implies \sf 3x=\dfrac{60}{2}$

$\implies \sf 3x=30$

Finding the value of x

$\implies \sf x=\dfrac{30}{3}$

$\implies \sf x=10$

Breadth = 10 cm

Length = 2x

Length = 10 × 2

= 20 cm

Therefore, length is 20 cm and breadth is 10 cm