Question

the length of a rectangle is twice its breadth if its perimeteris 60 cm find the length and the breadthof the rectangle​

Answer 1

Answer:

let breadth of rectangle be xcm

therefore length of rectangle will be 2x cm.

perimeter = 60 cm. (given)

perimeter of rectangle = 2 (l+b)

therefore. 60 = 2( x+2x)

60 = 6x

X =10

therefore

breadth = 10 cm

length = 10*2 =20cm

Answer 2

Given :

• Length of a rectangle is twice its breadth.
• Perimeter of Rectangle ia 60 cm.

To Find :

• Length and Breadth of Rectangle.

Solution :

$\longmapsto\tt{Let\:Breadth=x}$

As Given that Length of Rectangle is twice its breadth. So ,

$\longmapsto\tt{Length=2x}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}$

Putting Values :

$\longmapsto\tt{60=2(2x+x)}$

$\longmapsto\tt{\cancel\dfrac{60}{2}=2x+x}$

$\longmapsto\tt{30=3x}$

$\longmapsto\tt{x=\cancel\dfrac{30}{3}}$

$\longmapsto\tt\bf{x=10}$

Value of x is 10..

Therefore :

$\longmapsto\tt{Length=2(10)}$

$\longmapsto\tt\bf{20cm}$

$\longmapsto\tt\bf{Breadth=10cm}$

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• Perimeter of Rectangle = 2(l+b)
• Area of Rectangle = length × breadth.
• Diagonal of Rectangle = √(l)² + (b)².

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