Question

The length of a rectangle is twice its breadth. If its perimeter is 120 m, find the length and the breadth of the rectangle fast as ​

Answer 1

Answer:

l = 40m

b = 20m

Step-by-step explanation:

l = 2b

Given, perimeter, P = 120m

We know,

P = 2(l + b)

=> 120 = 2(2b + b) (using l = 2b)

=> 120 = 2(3b)

=> 120 = 6b

=> b = 120/6

b = 20

l = 2*20 = 40

Answer 2

Required answer:

• Length of rectangle = 40 m
• Breadth of rectangle = 20 m

Explanation:

Given information,

The length of a rectangle is twice its breadth. If its perimeter is 120 m, Find the length and the breadth of the rectangle.

• Length of rectangle = 2(Breadth of rectangle)
• Perimeter of rectangle = 120 m
• Length of rectangle = ?
• Breadth of rectangle = ?

Let,

• Breadth of rectangle = y
• As it is stated in question that length of a rectangle is twice its breadth. So, length of rectangle = 2y

ing formula,

✪ Perimeter of rectangle = 2(L + B) ✪

Where,

• L = length of rectangle
• B = breadth of rectangle

We have,

• L of rectangle = 2y
• B of rectangle = y
• Perimeter of rectangle = 120 m

Putting all values,

➻ 120 = 2(2y + y)

➻ 120 = 2(3y)

➻ 120 = 2 × 3y

➻ 120 = 6y

➻ 6y = 120

➻ y = 120/6

➻ y = 20

• Henceforth, breadth of rectangle is 20 m.

Now,

◐ Length of rectangle = 2y

Putting value of y,

◐ Length of rectangle = 2(20)

◐ Length of rectangle = 2 × 20

◐ Length of rectangle = 40 m

• Henceforth, length of rectangle is 40 m.

Verification,

➻ Perimeter of rectangle = 2(L + B)

Putting value of L and B,

➻ 120 = 2(40 + 20)

➻ 120 = 2(60)

➻ 120 = 2 × 60

➻ 120 = 120

➻ LHS = RHS

• Hence, Verified ✔

Know more,

• Perimeter of any figure is calculated by sum of its all sides.
• Perimeter of rectangle = 2(L + B)
• Perimeter of square = 4 × side
• Perimeter of circle = 2πr
• Perimeter of equilateral ∆ = 3 × side
• Perimeter of rhombus = 4 × side

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