Question

The length of a rectangle is twice its breadth. If its perimeter is 60 cm, find the length and the breadth of the rectangle..​

Answer 1

Answer:

length is 20cm and breadth is 10cm

explanation:let breadth be x

explanation:

P=2(L+B) (formula)

60=2(2x+x) (if length is twice of breadth, then length =2x)

60=2×3x

60=6x

x=60÷6

x=10

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Answer 2

Let's use the information given in the problem to write down some equations :—

Let L be the length of the rectangle and B be the breadth of the rectangle.

From the first sentence of the problem, we know that L = 2B.

From the second sentence of the problem, we know that the perimeter P of the rectangle is given by:

P = 2L + 2B

We can substitute L = 2B into this equation to get:

P = 2(2B) + 2B = 6B

We also know from the problem that the perimeter is 60 cm. So we can set 6B = 60 and solve for B:

6B = 60

6B = 60B = 10

Now that we know the breadth of the rectangle is 10 cm, we can use the equation L = 2B to find the length:

L = 2B = 2(10) = 20

★ So the length of the rectangle is 20 cm and the breadth of the rectangle is 10 cm.

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