Question

the length of a rectangle is twice its breadth. if the perimeter of the rectangle is 108m, find the dimensions of the rectangle.​

Answer 1

Ans:

Let length be=x

& breadth=2x

A.T.Q

2(l+b) =108

2(x+2x) =108

3x=108/2

3x=54

x=54/3

x=18

Length=18m

Breadth=2x

=2×18

=36m

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Answer 2

Answer:-

l = 36 cm

b = 18 cm

Given:-

l = 2b

Perimeter = 108 cm

To find :-

The dimension of rectangle.

Solution :-

Let the dimension of rectangle will be l and b respectively.

Then,

Perimeter of rectangle :-

★ $\boxed{\sf{ p = 2 (l+b) }}$

Put the given value of l.

→$108 = 2 ( l + b)$

→$108 = 2(2b + b )$

→$108 = 2 (3b)$

→$108 = 6b$

→$b = \dfrac{108}{6}$

→$b = 18cm$

Now put the value of b we get,

→l = 2b

→l = 2 × 18

→l = 36 cm