The length of a rectangle is twice its breadth. Its area is 128msq. Find its length and its perimeter
Answers
Given :-
- The length of a rectangle is twice its breadth. Its area is 128m²
To find :-
- Length and perimeter of rectangle
Solution :-
Let the breadth be x then length be 2x
- Area of rectangle = 128m²
As we know that
→ Area of rectangle = l × b
Where "l" is length and "b" is breadth
According to question
→ Area of rectangle = 128m²
→ l × b = 128
Put the value of length and breadth
→ 2x × x = 128
→ 2x² = 128
→ x² = 128/2
→ x² = 64
→ x = √64
→ x = ±8
- Length and breadth never in negative
So,
- x = 8 m
- Breadth of rectangle = x = 8m
- Length of rectangle = 2x = 16m
Now, perimeter of rectangle
→ 2(l + b)
Put the value of length and breadth
→ 2(16 + 8)
→ 2 × 24
→ 48m
Hence,
- Perimeter of rectangle is 48m
AnswEr :-
• Length of the rectangle is 16m
• Perimeter of the rectangle is 48m
Given :-
• The lengh of a rectangle is twice its breadth
• Area of the rectangle is 128m².
To Find :-
• Length and perimeter of the rectangle.
SoluTion :-
Let,
• Breadth of the rectangle be x
• Length will be 2x
• Area is 128m²
» Area of a rectangle is length × breadth
According to the question :-
→ Area of the rectangle = 128m²
→ Length × breadth = 128
→ 2x × x = 128
→ 2x² = 128
→ x² = 128/2
→ x² = 64
→ x = √64
→ x = ±8
• Breadth of the rectangle = x = 8m
• Length of the rectangle = 2x = 2 × 8 = 16cm
» Perimeter of a rectangle is 2 (length + breadth)
» 2 (8 + 16)
→ 2 × 24
→ 48m