Math, asked by mxixnn, 9 months ago

The length of a rectangle is twice its breadth. Its area is 128msq. Find its length and its perimeter

Answers

Answered by MяƖиνιѕιвʟє
31

Given :-

  • The length of a rectangle is twice its breadth. Its area is 128m²

To find :-

  • Length and perimeter of rectangle

Solution :-

Let the breadth be x then length be 2x

  • Area of rectangle = 128m²

As we know that

→ Area of rectangle = l × b

Where "l" is length and "b" is breadth

According to question

→ Area of rectangle = 128m²

→ l × b = 128

Put the value of length and breadth

2x × x = 128

→ 2x² = 128

→ x² = 128/2

→ x² = 64

→ x = √64

→ x = ±8

  • Length and breadth never in negative

So,

  • x = 8 m
  • Breadth of rectangle = x = 8m
  • Length of rectangle = 2x = 16m

Now, perimeter of rectangle

→ 2(l + b)

Put the value of length and breadth

→ 2(16 + 8)

→ 2 × 24

→ 48m

Hence,

  • Perimeter of rectangle is 48m
Answered by Anonymous
28

AnswEr :-

• Length of the rectangle is 16m

Perimeter of the rectangle is 48m

Given :-

• The lengh of a rectangle is twice its breadth

• Area of the rectangle is 128m².

To Find :-

• Length and perimeter of the rectangle.

SoluTion :-

Let,

Breadth of the rectangle be x

Length will be 2x

Area is 128m²

» Area of a rectangle is length × breadth

According to the question :-

→ Area of the rectangle = 128m²

Length × breadth = 128

2x × x = 128

→ 2x² = 128

→ x² = 128/2

→ x² = 64

→ x = √64

→ x = ±8

Breadth of the rectangle = x = 8m

Length of the rectangle = 2x = 2 × 8 = 16cm

» Perimeter of a rectangle is 2 (length + breadth)

» 2 (8 + 16)

→ 2 × 24

48m

Hence, perimeter of the rectangle is 48m.

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