The length of a rectangle is twice its width. If the perimeter of the rectangle is 60m, how do you find its area?
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Explanation:
Let
x
be the width of the rectangle
Then
2
x
is the length of the rectangle
The perimeter of the rectangle is equal to
2
×
length
+
2
×
width
ie
2
(
2
x
)
+
2
(
x
)
=
60
(Perimeter of rectangle is
60
)
4
x
+
2
x
=
60
6
x
=
60
x
=
10
That means that the width of the rectangle is
10
and the length of the rectangle is
20
.
The area of the rectangle is equal to
length
×
width
=
10
×
20
=
200m2
Let
x
be the width of the rectangle
Then
2
x
is the length of the rectangle
The perimeter of the rectangle is equal to
2
×
length
+
2
×
width
ie
2
(
2
x
)
+
2
(
x
)
=
60
(Perimeter of rectangle is
60
)
4
x
+
2
x
=
60
6
x
=
60
x
=
10
That means that the width of the rectangle is
10
and the length of the rectangle is
20
.
The area of the rectangle is equal to
length
×
width
=
10
×
20
=
200m2
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