Question

The length of a rectangle is twice its width. The perimeter is 60 ft. How do you find its area?

Answer 1

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width = z

length = 2z

Perimeter = 2( z +2z )

60. = 2 x 3z

60 / 2 = 3z

30 / 3. = z

10 = z

so ,

Length = 10 ft

Breadth = 2 x 10 = 20 ft.

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Answer 2

$\textbf{\underline{\underline{Answer :-}}}$

The area of the Rectangle is 200 sq.foot.

$\textbf{\underline{\underline{Explanation :-}}}$

$\textsf{\underline{\underline{Given : }}}$

The Length of Rectangle = twice its width

Perimeter of Rectangle = 60 feet.

$\textsf{\underline{\underline{To find :}}}$

Its area

$\textsf{\underline{\underline{Solution :}}}$

Consider the width as x

Consider the Length as 2x

★ Perimeter of Rectangle =

$\boxed{\sf{2(Length+Breadth)}}$

$\sf{\implies} \: 2(x + 2x) = 60$

$\sf{\implies} \: 2x + 4x = 60$

$\sf{\implies} \: 6x = 60$

$\sf{\implies} \: x = \dfrac{60}{6}$

$\sf{\implies} \: x = 10$

${\boxed{\sf{x = 10}}}$

Value of 2x

$\sf{\implies} \: 2 \times 10$

$\sf{\implies} \: 20$

$\boxed{\sf{Length = 20}}$

$\boxed{\sf{Breadth = 10}}$

★ Area of Rectangle :

$\boxed{\sf{Length \times Breadth}}$

$\sf{\implies} \: 20 \times 10$

$\sf{\implies} \:200$

$\sf{\implies} \:200 \: sq.foot$

$\therefore$ The area of the Rectangle is 200 sq.foot.