the length of a rectangle is twice of its breadth if its perimeter is 60 cm find its length
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Answers
Answer:
Let the breath = x
so length = 2x
perimeter of rectangle = 2(l+b)
60 = 2(2x + x )
60 = 2 × 3x
60 = 6x
x = 60/6
x = 10
hence, length is 2x = 20 cm
Given:
The length of the rectangle = 2 *( breadth of the rectangle)
The perimeter of the same rectangle = 60 cm.
To find:
The length of the rectangle.
Solution:
A rectangle is a form of a quadrilateral whose opposite sides are equal.
Let us name the rectangle EFGH.
The perimeter of the rectangle EFGH is,
Perimeter = 2 × (L + B)
Where L and B are the length and breadth of the rectangle, respectively.
Since the length of the rectangle, EFGH is twice the breadth of the rectangle EFGH.
Therefore,
L = 2B
Perimeter = 60 cm
60 = 2 × ( 2B + B)
60 = 2×( 3 B)
6 B = 60
B = 10
Breadth = 10 cm
The length = 2B = 2 × 10 = 20 cm
Hence, the length of the rectangle EFGH is equal to 20 cm.