the length of a rectangle is twice of its breadth if its perimeter of its 64 cm find the dimensions of the rectangle and area of rectangle
Answers
Answered by
9
Heya.... I think this can be ur answer dear!!
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given that
L= 2b ....
Perimeter =64
2(l+b) =64
2b+b=64/2 = 32
3b=32
b=10.67 cm
Now,
L=2(10.67) = 21.34cm...
_____________________________
____________________________
given that
L= 2b ....
Perimeter =64
2(l+b) =64
2b+b=64/2 = 32
3b=32
b=10.67 cm
Now,
L=2(10.67) = 21.34cm...
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Anonymous:
complete ur answer
Answered by
7
Let breadth be= x
Length is twice of breadtb
Then,
Length =2x
P=2(l+b)
64=2(2x+x)
64=2(3x)
64/2=3x
32=3x
32/3=x
Then
Breadth=32/3
Length =2*32/3cm=>64/3cm
Area=l*b
=64/3*32/3
=2048/9cm² or 277.56cm²
Length is twice of breadtb
Then,
Length =2x
P=2(l+b)
64=2(2x+x)
64=2(3x)
64/2=3x
32=3x
32/3=x
Then
Breadth=32/3
Length =2*32/3cm=>64/3cm
Area=l*b
=64/3*32/3
=2048/9cm² or 277.56cm²
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