Math, asked by mathsguy76, 3 months ago

The length of a rectangle is twice of its breadth. If its perimeter is 48 cm, find the dimensions
of the rectangle?
od 14 cm. The perimeter of the triangle is 36 cm. What​

Answers

Answered by tusharraj77123
3

Answer:

Dimensions -:

Length = 16 cm

Breadth = 8 cm

Step-by-step explanation:

Given :

Length is twice than Breadth

Perimeter = 48 cm

To find :

Their dimensions

Concept :

Let the Breadth be x

Let the Length be 2x

Using the perimeter formula to find the dimensions of the rectangle -:

\boxed{\sf{2(2x+x)=48cm}}

After we will get the value of x that will be the Breadth . And after that to find the length just do twice of it .

Solution :

:\implies\sf{2(2x+x)=48cm}

:\implies\sf{4x+2x=48cm}

:\implies\sf{6x=48cm}

:\implies\sf{x=\dfrac{\cancel{48}cm}{\cancel{6}}}

:\implies\sf{x=8cm}

So , the Breadth is 8 cm .

Length -:

:\implies\sf{8cm\times2}

:\implies\sf{16cm}

So , the length is 16 cm .

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