Question

the length of a rectangle is twice the breadth if the perimeter is 228 metres find the dimensions of the park​

Answer 1

Answer:

length of rectangle is 38m and y is 19m

Step-by-step explanation:

$let \: the \: length \: of \: rectangle \: be \: x \\ \\ and \\ \\ bredth \: of \: rectangle \: be \: y \\ \\ now \: according \: to \: question \\ \\ \\ \\ x = 2y \\ \\ now \: perimeter \: of \: rectangle = 2(x + y) \\ = 2(x + 2x) = 6x \\ \\ so \: 6x = 228 \\ \\ x = 38 \\ \\ and \: y = x \div 2 = 38 \div 2 = 19$

Answer 2

• Given

• Length of a rectangle is twice its breadth.
• Perimeter of rectangle = 228 m

• To find

• Dimensions of the park

• Concept

• We are given that the length of the rectangle is twice its breadth. So, we will let the breadth be x and the length be twice of it. That is, 2x.
• We have the value of perimeter of rectangle. By using the formula of perimeter of rectangle and substituting the values which we have let we will get the value of x.
• From there we will find the dimensions of rectangle by substituting the value of x in length and breadth.

• Solution

Let the breadth b x and length be 2x.

Perimeter of rectangle = 228 m

Using formula,

Perimeter = 2(l + b)

where,

• l = length of the rectangle
• b = breadth of the rectangle

Substituting the values,

⟶ 228 = 2(2x + x)

⟶ 228 = 2(3x)

⟶ 228 = 6x

⟶ 228/6 = x

⟶ 38 = x

The value of x = 38

Dimensions of rectangle -

• Length of rectangle = 2x = 2 × 38 = 76 m
• Breadth of rectangle = x = 38 m

_____________________________________

Let's verify -

Perimeter = 228 m

• Length = 76 m

• Breadth = 38 m

Perimeter = 2(l + b)

⟶ 2(76 + 38)

⟶ 2(114)

⟶ 228 m

Hence, verified.