Question

The length of a rectangle is twice the side of
a square and its width is 6 cm greater than the
side of the square. If area of the rectangle is
three times the area of the square; find the
dimensions of each.

Answer 1

QUESTION

The length of a rectangle is twice the side of  a square and its width is 6 cm greater than the  side of the square. If area of the rectangle is  three times the area of the square; find the  dimensions of each.

ANSWER

Let the square be of 'a'side then the area of rectangle will be [2a×(a+6)] because sides of rectangle will be ( length ) l=2a

$(breadth ) b=a+6$

then again from the question  

area of rectangle = 3× area of square

=$⇒2a 2 +6(2a)=3a ^{2}$

=$⇒3a 2 =6×2a+2a ^{2}$

=$⇒a ^{2} =12a$

=$so,a=12$

hence the answer is 12