Question

The length of a rectangle is two meters less than twice the width. The perimeter is 44 meters. Find the length and width.

Answer 1

Step-by-step explanation:

Let length and breadth the field are l and b respectively. Then,

Let length and breadth the field are l and b respectively. Then,l=2b−8⇒2b=8+l⟶(1)

Let length and breadth the field are l and b respectively. Then,l=2b−8⇒2b=8+l⟶(1)The perimeter of the rectangular field =56 m

Let length and breadth the field are l and b respectively. Then,l=2b−8⇒2b=8+l⟶(1)The perimeter of the rectangular field =56 m⇒2(l+b)=56m⇒2l+2b=56m

Let length and breadth the field are l and b respectively. Then,l=2b−8⇒2b=8+l⟶(1)The perimeter of the rectangular field =56 m⇒2(l+b)=56m⇒2l+2b=56mfrom (1), we get

Let length and breadth the field are l and b respectively. Then,l=2b−8⇒2b=8+l⟶(1)The perimeter of the rectangular field =56 m⇒2(l+b)=56m⇒2l+2b=56mfrom (1), we get2l+8+l=56⇒3l=48⇒l=16m

Let length and breadth the field are l and b respectively. Then,l=2b−8⇒2b=8+l⟶(1)The perimeter of the rectangular field =56 m⇒2(l+b)=56m⇒2l+2b=56mfrom (1), we get2l+8+l=56⇒3l=48⇒l=16m∴ Length of rectangular field =16m

Let length and breadth the field are l and b respectively. Then,l=2b−8⇒2b=8+l⟶(1)The perimeter of the rectangular field =56 m⇒2(l+b)=56m⇒2l+2b=56mfrom (1), we get2l+8+l=56⇒3l=48⇒l=16m∴ Length of rectangular field =16mBreadth of rectangular field =

Let length and breadth the field are l and b respectively. Then,l=2b−8⇒2b=8+l⟶(1)The perimeter of the rectangular field =56 m⇒2(l+b)=56m⇒2l+2b=56mfrom (1), we get2l+8+l=56⇒3l=48⇒l=16m∴ Length of rectangular field =16mBreadth of rectangular field = 2

Let length and breadth the field are l and b respectively. Then,l=2b−8⇒2b=8+l⟶(1)The perimeter of the rectangular field =56 m⇒2(l+b)=56m⇒2l+2b=56mfrom (1), we get2l+8+l=56⇒3l=48⇒l=16m∴ Length of rectangular field =16mBreadth of rectangular field = 216+8

Let length and breadth the field are l and b respectively. Then,l=2b−8⇒2b=8+l⟶(1)The perimeter of the rectangular field =56 m⇒2(l+b)=56m⇒2l+2b=56mfrom (1), we get2l+8+l=56⇒3l=48⇒l=16m∴ Length of rectangular field =16mBreadth of rectangular field = 216+8

Let length and breadth the field are l and b respectively. Then,l=2b−8⇒2b=8+l⟶(1)The perimeter of the rectangular field =56 m⇒2(l+b)=56m⇒2l+2b=56mfrom (1), we get2l+8+l=56⇒3l=48⇒l=16m∴ Length of rectangular field =16mBreadth of rectangular field = 216+8 =12m

Answer 2

Step-by-step explanation:

Given:-

The length of a rectangle is two meters less than twice the width. The perimeter is 44 meters.

To find:-

Find the length and width.

Solution:-

Let the width of the rectangle=X m

Then, Length of the rectangle

=2 m less than twice the width

=>(2X-2) m

Length =(2X-2) m

Perimeter of a rectangle=2(length+width) units

=>Perimeter=2(2X-2+X) m

=>Perimeter=2(3X-2) m

=>Perimeter=6X-4 m

According to the given problem,

Perimeter of the rectangle=44m

=>6X-4=44

=>6X=44+4

=>6X=48

=>X=48/6

=>X=8 m

Therefore Width =8m

length=2X-2=2(8)-2=16-2=14 m

Answer:-

Length of the given rectangle =14 m

Width of the given rectangle =8 m

Check:-

width =8m

Twice the width =2(8)=16 m

Length =16-2=14 m

Perimeter=2(14+8)

=>2(22)

=>44m

Verified the given relations in the problem.