Question

The length of a rectangle is two times its width. The perimeter of a rectangle is 180cm . Find the dimensions of the rectangle.​

Answer 1

$\color{red}{\huge{\bf {\boxed{\mathcal{\bigstar{\color{blue}{..!!Hello..Mate!!..}}}}}}}$

$\color{orange}{\bf{\underline{\huge{Given\: :}}}}$

let the breadth be " X "

Length is twice the breadth = 2X

perimeter of the rectangle = 180 cm

But according to problem...

2 (L + b) = 180 cm

2 ( X + 2X ) = 180

2 ( 3X) = 180

6X = 180

X = 180/6 = 30 cm

So,

Therefore,

Breadth = x = 30 cm

length = 2x = 2 x 30 = 60 cm

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Answer 2

$\underbrace{ \boxed{ \tt \pink S \gray ol \blue ut \red io \purple n}}$

Let the width of the rectangle be x.

It is given that the length of the rectangle is twice its width, so the length is 2x.

Now,

We know that the perimeter of a rectangle is twice the sum of its length and width.

The perimeter is given as 180 cm.

So, Perimeter of rectangle = 2(L+B)

$\implies \red{ \tt 180cm = 2(2 x+ x)}$

$\implies \blue{ \tt 180cm = 4 x+ 2x}$

$\implies \purple{ \tt 180cm = 6x}$

$\implies \pink{ \tt \frac{ \cancel{180}}{ \cancel6} = x}$

$\implies \gray{ \tt x = 30cm}$

$\tt So, the \: width \: of \: rectangle \: is \\ \tt x = 30cm \: and \: the \: length \: of \: rectangle \\ \tt is \: 2x = 2 \times 30 = 60cm.$

$\huge \tt Hence, \: dimensions \\ \huge \tt of \: rectangle \: is \\ \huge \boxed{ \tt30 \times 60}$