Question

The length of a rectangle os twice that of its breadth. If the length of the rectangle is increased by 20%, determine the percentage change, if any, in its perimeter​

Answer 1

Step-by-step explanation:

L = 2B

P = 2(L + B)

P = 2(2B + B) = 6B

L' = 1.2L

P' = 2(1.2L + B)

P' = 2(1.2× 2B + B)

P' = 6.8B

percentage increase = 6.8/6.0 × 100

=113.33...means 13.3 % increase