Question

the length of a rectangle shaped park exceed its breadth by 17 meters .if the perimeter of the park is 178 meters find the dimension of the park

Answer 1

Let,
The breadth of the park be x m,
Length of the park be (x+17) m

___________

Perimeter of rectangle =2(lenght + breadth)

Here,

178= 2(x + x+ 17)

178/2 = x + x+ 17

89 = 2x + 17

89-17 = 2x


72 = 2x

72/2 = x

36= x

, _____________, _

Then,

Breath of park = x = 36 m

Length of the park = x +17 = 36+17 = 53 m


I hope this will help you


-by ABHAY

Answer 2

Answer:

Let the breadth of the park be = x metres

Then the length of the park be = x±17 metres

perimeter of the park=2( length ±breadth)

=2(x±17±x) metres

=2(2x±17) metres

But it is given that the perimeter of the rectangle is 178 metres.

2(2x ±17) =178

4x±34=178

4x =178-34

4x=144

x=144/4=36

Therefore breadth of the park=36 metres

Length of the park=36±17=53 metres.

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