The length of a rectangle, whose perimeter is 88 m and breadth is 12 m, is
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Answered by
5
We know perimeter of rectangle = 2(L+B)
2( L + 12) = 88
2L + 24 = 88
2L = 88-24
2L = 64
L = 32
Hence our answer is 32m
Thank you
Answered by
107
Question : The length of a rectangle, whose perimeter is 88 m and breadth is 12 m, is.
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Answer : 32
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Solution → Length = ?
→ Breath = 12 m
→ Perimeter = 84
→ Perimeter of rectangle = 2(l+b)
→ 88 = 2(L+12)
→ 88 = 2 × L + 2×12
→ 88 = 2×L +24
→ 88 -24 = 2×L
→ 64 = 2×L
→ L = 64/2
→ Length = 32
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