The length of a rectangle, Whose perimeter is 88m and breadth is 12m,is
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Answered by
78
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We have to find the length of the rectangle
Where ,
Breadth and perimeter is given ..
b = 12 m
and perimeter = 88
As we know ..
Perimeter of rectangle = 2( l + b)
Where l is length b is breadth ..
2 ( l + 12 ) = 88
2l = 88 - 24
2l = 64
l = 64/2
l = 32
The length of rectangle is 32 m ..
================
I HOPE IT WILL HELP You
Thank you
☺️
Here is your answer
⬇️⬇️⬇️⬇️⬇️
We have to find the length of the rectangle
Where ,
Breadth and perimeter is given ..
b = 12 m
and perimeter = 88
As we know ..
Perimeter of rectangle = 2( l + b)
Where l is length b is breadth ..
2 ( l + 12 ) = 88
2l = 88 - 24
2l = 64
l = 64/2
l = 32
The length of rectangle is 32 m ..
================
I HOPE IT WILL HELP You
Thank you
☺️
pranshu5674:
Thanks
Answered by
16
The perimeter of rectangle = 88
as we know the formula of perimeter of rectangle 2(l + b)
breadth = 12 m
Length = l
2(l + 12) = 88
l + 12 = 44
l = 44 - 12
l = 32
The length of rectangle is 32 m ..
as we know the formula of perimeter of rectangle 2(l + b)
breadth = 12 m
Length = l
2(l + 12) = 88
l + 12 = 44
l = 44 - 12
l = 32
The length of rectangle is 32 m ..
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