Question

The length of a rectangular deck is 4 times its width. If the deck’s perimeter is 20 feet, what is the deck’s area?

Answer 1

Answer:

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Answer 2

Dimensions of a rectangular deck :

$Let \: width = x \: feet , \: and \\Length = 4 \times width \\= 4x \: feet$

$\blue{ Perimeter \: of \: the \: deck }\\= 20 \:feet \: (given)$

$\implies 2( l + w ) = 20$

$\implies 2( 4x + x ) = 20$

$\implies 2\times 5x = 20$

$\implies 10x = 20$

$\implies x = \frac{20}{10}$

$\implies x = 2\: --(1)$

$\red{ Area \: of \: the \:deck } \\= l \times w \\= 4x \times x \\= 4x^{2} \\= 4 \times (2)^{2} \: \blue{[ From \: (1) ]}\\= 4 \times 4 \\= 16 \: square \: feet$

Therefore.,

$\red{ Area \: of \:the \: deck }\\\green { = 16 \: square \: feet}$

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