The length of a rectangular farm is (2x + 5) m and its width is (x+4) m. The perimeter of the farm is 102 m.
Answers
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Question : The length of a rectangular farm is (2x + 5) m and its width is (x+4) m. The perimeter of the farm is 102 m. Find the length and the breadth and area of the rectangular farm.
Solution :
➜ Length of farm = (2x + 5) m ----{1}
➜ Breadth of farm = (x + 4) m ----{2}
➜ Area of farm = 102 m ----{3}
Now, by formula of perimeter of rectangle;
➜ Per =2 * {length + breadth}
➜ 102 = 2 * {(2x + 5) + (x + 4)}
➜ 102 = 2 * {2x + 5 + x + 4}
➜ 102 = 2 * {2x + x + 5 + 4}
➜ 102 = 2 * {3x + 9}
➜ 102 = 6x + 18
➜ 6x = 102 - 18
➜ 6x = 84
➜ x = 84/6
➜ x = 14
Now, put value of x in eq. {1} and eq. {2}
➜ Length of farm = (2x + 5) m
➜ Length of farm = (2 * 14 + 5) m
➜ Length of farm = (28 + 5) m
➜ Length of farm = 33 m and
➜ Breadth of farm = (x + 4) m
➜ Breadth of farm = (14 + 4) m
➜ Breadth of farm = 18 m
Now, by formula area of rectangle;
➜ Area of farm = Length * breadth
➜ Area of farm = 33 * 18
➜ Area of farm = 594 m²
Answer : Hence, the length and the breadth of the rectangular farm are 33 m and 14 m respectively. And the area of the farm is 594 m².