the length of a rectangular feild is greater than its width by 4 meter if the primeter of feild is 32 meter find the area
Answers
Answered by
2
Let the width be x
Length=x+4
According to the question
2(x+4+x)=32
2x+8+2x=32
4x=32-8
4x=24
x=24/4=6
width=x=6m
length=x+4=6+4=10
So area of the field=10*6=60sq. m
Length=x+4
According to the question
2(x+4+x)=32
2x+8+2x=32
4x=32-8
4x=24
x=24/4=6
width=x=6m
length=x+4=6+4=10
So area of the field=10*6=60sq. m
Answered by
1
2(12+4)
2(16)
=32
p=2(l+b)
area A =l*b
l=12
b+4
=48
2(16)
=32
p=2(l+b)
area A =l*b
l=12
b+4
=48
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