Question

the length of a rectangular feild is thirce of its breadth if the perimeter of the feild is 300m. then find the length and breadth of the feild
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Answer 1

Answer:

Let breadth=x

Length=3x

Perimeter =2(l+b)

2(3x+x)= 300

2(4x)=300

8x =300

X=300/8 =37.5

Breadth=37.5m

Length = 112.5 m

Answer 2

Answer:

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

The length of a rectangular field is thrice of its breadth if the perimeter of the field is 300m. then find the length and breadth of the field

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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Let the breadth of the Rectangle be$\bold{\red{ 'x'm}}$

then ,length of the Rectangle be$\bold{\red{ 3x}}$

Given : Perimeter of the field is 300m

Formula:

$\bold{\boxed{Perimeter \:of \:rectangle = 2(l + b)}}$

= > 300 = 2(3x + x)

= > 300 = 8x

= > 8x = 300

$= > x = \frac{300}{8} = 37.5$

Hence,breadth of the Rectangle is $\bold{\red{37.5m}}$

Length of the Rectangle is 3x=3×37.5=$\bold{\red{112.5m}}$

let's check by putting values in the formula:

$\implies\bold{ 2(l + b) = 300}$

$\implies\bold{2(112.5 + 37.5) = 300}$

$\implies\bold{ 2(150) = 300}$

$\implies\bold{ 300 = 300}$

=>Look above image attached for figures of square, rectangular, triangle & circle .

$\Large\mathscr\color{red}{LEARN\:MORE:-}$

$\boxed{\frak{Area \:of\: rectangle = l \times b}}$

$\boxed{\frak{Area \:of\: square = {(side)}^{2}}}$

$\boxed{\frak{Area\: of\: triangle = \frac{1}{2} base \times height}}$

$\boxed{\frak{Area \:of \:circle = \pi {r}^{2} }}$

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