Question

The length of a rectangular field exceeds its
breadth by 100 metres. If the perimeter of
the field is 1000 metres, find the dimensions
of the field.​

Answer 1

Answer:

The Length is 300 m and Breadth is 200 m.

Step-by-step explanation:

Given :

Length of the rectangle = 100 m more than its breadth

Perimeter = 1000 m

To find :

The dimensions of the rectangle

Solution :

Let the -

• Breadth be y
• Length be (y + 100)

$\bigstar \: \boxed{\sf{Perimeter = 2(Length + Breadth)}}$

$\sf{\implies} \: 1000 = 2(y +100 + y) \\ \\ \sf{\implies} \: 1000 = 2(2y + 100) \\ \\ \sf{\implies} \: 1000 = 4y + 200 \\ \\ \sf{\implies} \: 4y = 1000 - 200 \\ \\ \sf{\implies} \: 4y = 800 \\ \\ \sf{\implies} \: y = \dfrac{800}{4} \\ \\ \sf{\implies} \: y = 200$

Breadth = 200 m

$\rule{300}{1.5}$

★ $\textsf{\underline{\underline{Value of (y + 100) }}}$

$\sf{\implies} \: 200 + 100 \\ \\ \sf{\implies} \: 300$

Length = 300 m

$\therefore$ The Length is 300 m and Breadth is 200 m.

Answer 2

Answer:

Suppose breath be = y

and length be (y + 100).

Formula of perimeter:

2(length + breadth).

1000 = 2(y + 100 + y) .

1000= 2(2y + 100) ..(2y Because there are two y).

1000 = 4y + 200.

4y =1000 - 200.

4y = 800.

y = 200.

Value of (y + 100).

= 200 + 100.

= 300.

Breadth = 200 and length = 300 .

#answerwithquality #BAL.