the length of a rectangular field exceeds its breadth by 5m if the perimeter of the field is 142 me find the dimensions of the field
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5
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Answered by
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Let the breadthof field is x
and length is (x+5)
the perimeter of rectangle = 2(x+y)
142 = 2 × x + (x+5)
142 = 2 ×( 2x + 5 )
142 = 4x+ 10
132 = 4x
132\4 = x
33 = x
then the breadth is 33 m and
length is 38 m
and length is (x+5)
the perimeter of rectangle = 2(x+y)
142 = 2 × x + (x+5)
142 = 2 ×( 2x + 5 )
142 = 4x+ 10
132 = 4x
132\4 = x
33 = x
then the breadth is 33 m and
length is 38 m
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