Math, asked by shreyashi0909, 2 months ago

The length of a rectangular field is 100 m. If the perimeter is 300 m, what is its breadth?
with explanation ​

Answers

Answered by itscandycrush
102

Answer:

Question:-

▪︎The length of a rectangular field is 100 m. If the perimeter is 300 m, what is its breadth?

Formula Used:-

▪︎Perimeter of Rectangular = 2(length+breadth)

Solution:-

Given:

▪︎Length of field = 100m

▪︎Perimeter of field = 300m

To Find:

▪︎Breadth of field = ???

Answer:

Let the breadth of Rectangular field be x m.

According to given conditions;

Perimeter of field = 300m

= 2(l+b) = 300m

= 2(100+x) = 300m

= 100+x = 300÷2

= x = 150-100

Hence,

x = breadth = 50m

More to know:-

Area of rectangle = length × breadth

Perimeter of rectangle = 2(length+breadth)

Area of square = (side)²

Perimeter of square = 4× side

Answered by SarcasticL0ve
66

\bf Given\begin{cases} & \sf{Length\:of\;rectangular\;field = \bf{100\;m}}  \\ & \sf{Perimeter\;of\;rectangular\;field = \bf{300\;m}}  \end{cases}\\ \\

To find: Breadth of rectangular field?

⠀⠀⠀⠀_____________________________

☯ Let breadth of rectangular field be x m.

⠀⠀⠀⠀

\setlength{\unitlength}{0.9cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 100 m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large x m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\

\star\;{\boxed{\sf{\pink{Perimeter_{\;(rectangle)} = 2(length + breadth)}}}}\\ \\

Therefore,

⠀⠀⠀⠀

{\underline{\sf{\bigstar\: According\:to\:the\:question\::}}}\\ \\

:\implies\sf 2(100 + x) = 300\\ \\

:\implies\sf (100 + x) = \cancel{\dfrac{300}{2}}\\ \\

:\implies\sf 100 + x = 150\\ \\

:\implies\sf x = 150 - 100\\ \\

:\implies{\underline{\boxed{\sf{\purple{x = 50}}}}}\;\bigstar\\ \\

\therefore\;{\underline{\sf{Breadth\:of\;rectangular\;field\;is\; {\textsf{\textbf{50\;m}}}.}}}

⠀⠀⠀⠀_____________________________

\qquad\qquad\boxed{\bf{\mid{\overline{\underline{\pink{\bigstar\: More\:to\:know :}}}}}\mid}\\\\

  • Area of rectangle = length × breadth

  • Diagonal of rectangle = √(length)² + (breadth)²

  • Area of square = side × side

  • Perimeter of square = 4 × side

  • Diagonal of square = √2 × side
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