Question

The length of a rectangular field is 20 m and its perimeter is 50m. Find its breadth.

Answer 1

Step-by-step explanation:

peri. if rectangle= 2(l+b)

50= 2(20+b)

25= 20+b

5= b

hence breadth of rectangle is 5m

#666

Answer 2

Answer :-

• The breadth of the rectangular field is 5 m.

Given :-

• The length of the rectangular field is 20 m.
• It's perimeter is 50 m.

To find :-

• The breadth of the rectangular field.

Step-by-step explanation :-

The question has given us the perimeter and length. We have to find the breadth.

For this, we are gonna use the formula required for finding the perimeter of a rectangle.

Let's assume that the breadth is b.

We know that :-

Perimeter of a rectangle = Length × Breadth.

So, lets apply the formula.

We get :-

$\sf2 \: (20 \: m + b) = 50 \: m$

Removing the brackets,

$\sf40 \: m + 2b = 50 \: m$

Transposing 40 from LHS to RHS, changing it's sign,

$\sf2b = 50 \: m - 40 \: m$

On subtracting the numbers,

$\sf2b = 10 \: m$

Transposing 2 from LHS to RHS, changing it's sign,

$\sf b = \dfrac{10 \: m}{2}$

Dividing 10 m by 2,

$\sf b = 5 \: m.$

Therefore, the breadth of the rectangular field is 5 m.

Verification :-

To check our answer, let's apply the formula of finding the perimeter of a rectangle (Since we now have the length and breadth, along with the perimeter) and see if we get the perimeter after multiplying the length and breadth by 2 and then adding them.

Lets proceed!

$\sf2 \: (20 \: m + 5 \: m)$

Removing the brackets,

$\sf40 \: m + 10 \: m$

On adding the numbers,

$\sf\Rightarrow50 \: m.$

Since we got the perimeter,

Hence verified!