Question

The length of a rectangular field is 3 units more than breadth and the perimeter is 22 units . Find the dimensions of the rectangular field.​

Answer 1

Answer:

Step-by-step explanation:

Let x be the breadth of rectangle.

Therefore,

Length of rectangle (l)=(x+3)

Perimeter of rectangle =38m

As we know that,

Perimeter of rectangle =2(l+b)

∴2((x+3)+x)=38

⇒2x+3=  

2

38

​  

 

⇒2x=19−3

⇒x=  

2

16

​  

=8m

Therefore,

l=x+3=8+3=11m

Hence the length and breadth of rectangle is 11m and 8m respectively.

Answer 2

AnswEr :-

• Breadth of the rectangle is 4 units.
• Length of the rectangle is 7 units.

Given :-

• The length of a rectangular field is 3 units more than its breadth and the perimeter is 22 units.

To Find :-

• The dimensions of the rectangular field.

SoluTion :-

• It is given that the length of the rectangular field is 3 units more than its breadth. So, we've to consider breadth as x units and length as x + 3 units.

Let,

• Breadth = x units
• Length = x + 3 units

Here,

• Perimeter of the rectangle is 22 units.

We know that the perimeter of the rectangle is

2 (l + b)

Where,

• l = length
• b = breadth

According to question :-

2 (x + x + 3) = 22

→ 2 (2x + 3) = 22

→ 2x + 3 = 22/2

→ 2x + 3 = 11

→ 2x = 11 - 3

→ 2x = 8

→ x = 8/2

→ x = 4

Hence,

• Breadth of the rectangle is 4 units.
• Length of the rectangle is 4 + 3 = 7 units

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