Question

The length of a rectangular field is 30 m and its diagonal is 34 m. Find the breadth
of the field and its perimeter.

Answer 1

It's given that ,

$\sf{Length\:of\:a\:rectangular\:field\:= 30 m}$

$\sf{Diagnoal\:of\:a\:rectangular\:field\:= 34 m}$

Consider the breadth of rectangular field = b m

Using the pythagoras theorem ,

$\sf{{AC}^{2}={AB}^{2} + {B}^{2}}$

Substituting the values

$\sf{{34}^{2}={30}^{2} + {b}^{2}}$

$\sf{BY\:further\:calculation}$

$\sf{1156=900+{b}^{2}}$

$\sf{So\:we\:get}$

$\sf{{b}^{2}=1156-900=256}$

$\sf{b=\sqrt256=16m}$

$\sf{We\:all\:know\: that,}$

$\sf{Perimeter\:=2(l+b)}$

$\sf\longrightarrow{2(30+16)}$

$\sf\longrightarrow{2\times46}$

$\sf\longrightarrow{92m}$