The length of a rectangular field is 400m and its breadth is 5/8 of its length.If a road of width 12m is built along the inner wall of he field, dind the area of the road.
Answers
Answered by
4
Length of field = 400 m
Width of field = 5*400/8
= 5 * 50
= 250 m
Area of field = 400 * 250
= 100000 m^2
Length of Outer rectangle = 400 + 12 + 12
= 424 m
Width of outer rectangle = 250 + 12 + 12
= 274 m
Area of outer rectangle = 424 * 274
= 116176 m^2
Area of road = Area of outer rectangle - Area of field
Area of road = 116176 - 100000
= 16176 m^2
Width of field = 5*400/8
= 5 * 50
= 250 m
Area of field = 400 * 250
= 100000 m^2
Length of Outer rectangle = 400 + 12 + 12
= 424 m
Width of outer rectangle = 250 + 12 + 12
= 274 m
Area of outer rectangle = 424 * 274
= 116176 m^2
Area of road = Area of outer rectangle - Area of field
Area of road = 116176 - 100000
= 16176 m^2
Similar questions
Math,
7 months ago
Chemistry,
7 months ago
English,
7 months ago
Biology,
1 year ago
India Languages,
1 year ago