Question

The length of a rectangular field is 6 meter more than twice its breadth. if the Perimeter of the field is 132 meters, find the length and breadth of the field.
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Answer 1

Answer:

Let the breadth of the field be \(x\)

Then , length of the field =\(2x+6\)

Perimeter of the field \(=132\) m

So,\(2(l+b)=132\)

\(\implies 2(x+2x+6)=132\)

\(\implies 2(3x+6)=132\)

\(\implies 3x+6=66\)

\(\implies 3x=60\)

\(\implies x=\frac{60}{3}=20\)

Hence, breadth of the field is \(20\) m and length of the field is \(2\times 20+6=46\)m.

Answer:46m,20 m

Step-by-step explanation:

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Answer 2

Answer:

length = 46m , breadth = 20 m

step-by-step explanation:

let the breadth of the field be x

and the length = (2x + 6)

perimeter=132

According to question

perimeter=2( l+ b ) = 132

= 2 ( 2x + 6 + x ) =132

= 4x + 12 + 2x =132

= 4x + 2x + 12 =132

= 6x + 12 = 132

= 6x = 132- 12

=6x = 120

= x = 120/6

= x= 20 ( breadth)

= length= ( 2x + 6 ) = ( 2× 20 + 6 ) = 46