Question

the length of a rectangular field is 8 M less than twice its breadth if the perimeter of the rectangular field is 56 M find its length and breadth

Answer 1

Let the breadth of rectangle(b) = x m
then length(l) = (2x-8) m
A/q,
perimeter of rectangle = 56 m
⇒ 2(l+b) = 56
⇒ 2(2x-8+x) = 56
⇒ 3x-8 = 28
⇒ 3x =28+8
⇒ x = 36/3 = 12 m
therefore length(l) = 2x-8 =2×12 - 8 =16 meters
breadth(b) = x = 12 meters