Question

The length of a rectangular field is 8 m less than twice its breadth. Find the dimensions of the
field, if its perimeter is 158 m.
plz explain​

Answer 1

To Find:-

• Find the length of rectangle.

Given:-

• The length is 8m less than twice it's breadth.
• The perimeter of rectangle is 158m.

Solution:-

Let the breadth be " b "

So,

l = 2b - 8

Perimeter of rectangle = 2( l + b )

$\tt \implies { \: 158 \: = \: 2 \: ( \: 2b \: - \: 8 \: + \: b\: ) \: }$

$\tt \implies { \: 158 \: = \: 2 \: ( \: 3b \: - \: 8 \: ) \: }$

$\tt \implies { \: 158 \:\: = \: 6b \: - \: 16 \: }$

$\tt \implies { \: 158 \: \: + \: 16 \: = \: 6b \: }$

$\tt \implies { \: 174 \: = \: 6b \: }$

$\tt \implies { \: b \: = \: \cancel \frac{174}{6} \: }$

$\tt \implies\boxed { \: b \: = \: 29 \: }$

So,

$\tt \implies { \: length \: = \: 2b \: - \: 8 \: }$

$\tt \implies { \: l \: = \: 2 ( \: 29 \: ) \: - \: 8 \: }$

$\tt \implies { \: l \: = \: 58 \: - \: 8 \: }$

$\tt \implies\boxed { \: l \: = \: 50 \: }$

Answer 2

Answer:

To Find:-

Find the length of rectangle.

Given:-

The length is 8m less than twice it's breadth.

The perimeter of rectangle is 158m.

Solution:-

Let the breadth be " b "

So,

l = 2b - 8

Perimeter of rectangle = 2( l + b )

158=2(2b−8+b)

158 = 4b - 16 + 2b

158 = 6b - 16

158+16 = 6b

6b = 174

b = 174/6

b = 29

length = 2b-8

= 2×29-8

= 58-8

= 50