Question

the length of a rectangular field is 8 m less than twice its breadth of the perimeter of the rectangular field is 59 meters find its length and breadth​

Answer 1

Answer:

• Length is 8 meter less than twice of breadth of rectangular field
• Perimeter = 59 meters

Let the Breadth be n and Length be (2n - 8) of the rectangular field

• According to the Question :

⇒ Perimeter = 2(L + B)

⇒ 59 = 2{(2n - 8) + n}

⇒ 59 = 2{2n - 8 + n}

⇒ 59 = 2{3n - 8}

⇒ 59 = 6n - 16

⇒ 59 + 16 = 6n

⇒ 75 = 6n

⇒ 75/6 = n

⇒ n = 12.5

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• Sides of the rectangular field :

⇢ Length = (2n - 8)

⇢ Length = (2*12.5 - 8)

⇢ Length = (25 - 8)

⇢ Length = 17 m

⇢ Breadth = n

⇢ Breadth = 12.5 m

∴ Hence, length and breath of rectangular field are 17 m and 12.5 m respectively.

Answer 2

Answer :

$\underline{\underline{\sf{\blue{Given\::-}}}}$

The length of a rectangular field is 8 m less than twice its breadth of the perimeter of the rectangular field is 59 meters

$\underline{\underline{\sf{\blue{To\:Find\::-}}}}$

Its length and breadth

$\underline{\underline{\sf{\blue{Solution\::-}}}}$

Let the breadth be b and lenght be (2n - 8) of the rectangle field

As we know,

Perimeter of rectangle = 2 (l + b)

According to question,

➡ Perimeter of rectangle = 2 (l + b)

➡ 59m = 2 {(2b-8)+b}

➡ 59m = 2 {2b-8+b}

➡ 59m = 2 {3b-8}

➡ 59m = 6b - 16

➡ 59m + 16m = 6b

➡ 75m = 6n

➡ 75/6m = n

➡ n = 12.5

Therefore,

Length = (2n-8)

Length =(2×12.5-8)

Length = 17m

And

Breath = b = 12.5 m