Question

The length of a rectangular field is 8 meters less than twice its breadth the perimeter
of
the rectangular field is 56 meters, find its length and breadth​

Answer 1

Step-by-step explanation:

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Answer 2

Solution :

$\underline{\bf{Given\::}}}}$

The length of a rectangular field is 8 meters less than twice it's breadth & the perimeter of rectangular field is 56 m.

$\underline{\bf{Explanation\::}}}}$

Let the breadth of rectangular field be r m & the length of the rectangular field be (2r - 8) m respectively;

As we know that formula of the perimeter of rectangle;

$\boxed{\bf{Perimeter = 2(length + breadth)}}}}$

A/q

$\longrightarrow\sf{2[(2r - 8) + r] =56}\\\\\longrightarrow\sf{2(2r - 8 + r)=56}\\\\\longrightarrow\sf{2(3r-8) = 56}\\\\\longrightarrow\sf{6r - 16 = 56}\\\\\longrightarrow\sf{6r = 56 + 16}\\\\\longrightarrow\sf{6r = 72}\\\\\longrightarrow\sf{r=\cancel{72/6}}\\\\\longrightarrow\bf{r=12\:m}$

Thus;

$\boxed{\sf{Length\:of\:rectangular\:field = (2r-8)m = [2(12) - 8] = [24 - 8] = \boxed{\bf{16\:m}}}}\\\boxed{\sf{Breadth\:of\:rectangular\:field = r = \boxed{\bf{12\:m}}}}$