Question

the length of a rectangular field is 8 meters less than twice its breadth .If the perimeter the rectangular field is 56 meters ,find its length and breadth​

Answer 1

Given:-

The length of a rectangular field is 8 meters less than twice its breadth.

The perimeter the rectangular field is 56m

To Find:-

The length and breadth of Rectangle.

Formulae used:-

Perimeter of Rectangle = 2( L + B ).

Now,Atq

Let the Breadth be "x"

→ Length of Rectangle = 2x - 8

Now,

→ Perimeter of Rectangle = 2 ( L + B )

→ 56 = 2 ( 2x - 8 + x )

→ 56/2 = 2x - 8 + x

→ 28 = 3x - 8

→ 28 + 8 = 3x

→ 36 = 3x

→ x = 36/3

→ x = 12

So, The Breadth of Rectangle is 12m.

→ Length of Rectangle → 2x - 8 → 24 - 8 → 16m

Hence, The length and Breadth of Rectangle is 16m & 12m respectively.

Answer 2

Answer:

Let the length of the rectangular field be l

and let the breadth be b. Then,

According to the question,

l = 2b – 8 .....(1)

Since the field is rectangular it's perimeter

= 2(l + b)

$= > 56 = 2(2b - 8+ b) \\ \\ = > \frac{56}{2} = 2b - 8 + b \\ \\ = > \frac{56}{2} = 2b + b - 8 \\ \\ = > 28 = 3b - 8 \\ \\ = > 28 + 8 = 3b \\ \\ = > 36 = 3b \\ \\ = > b = \frac{36}{3} \\ \\ = 12$

breadth of the rectangular field = 12 metres.

Now, length = 2b – 8

= 2 × 12 – 8

= 24 – 8

= 16 metres.

Hence, length of the rectangular field is 16 m and breadth is 12 m.