The length of a rectangular field is 8 meters less than twice its breadth. If the perimeter of
the rectangular field is 56 meters, find its length and breadth?
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17
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Let length and breadth the field are l and b respectively. Then,
l=2b−8⇒2b=8+l⟶(1)
The perimeter of the rectangular field =56 m
⇒2(l+b)=56m⇒2l+2b=56m
from (1), we get
2l+8+l=56⇒3l=48⇒l=16m
∴ Length of rectangular field =16m
Breadth of rectangular field =
2
16+8
=12m
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Answered by
2
@she_owned_me
Let length and breadth the field are l and b respectively. Then,
l=2b−8⇒2b=8+l⟶(1)
The perimeter of the rectangular field =56 m
⇒2(l+b)=56m⇒2l+2b=56m
from (1), we get
2l+8+l=56⇒3l=48⇒l=16m
∴ Length of rectangular field =16m
Breadth of rectangular field =
2
16+8
=12m
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