Question

the length of a rectangular field is 8 meters less than twice its breadth. if the perimeter of the rectangular field is 56 meters, find its length and breadth​

Answer 1

Step-by-step explanation:

Perimeter of a Rectangle = 2(l+b)

Given that,

perimeter = 56,

length is 8 mtrs less than twice the breadth.

Let x = breadth,

length = 2x-8.

let's solve now :-

56 = 2{(2x-8)+x}

56 = 4x -16 + 2x

56 = 6x -16

6x = 56+16

x = 72/6

x = 12

now,

breadth,x = 12 and length,2x-8 = 2(12)-8 = 16

Answer 2

☆ Solution ☆

Given :-

• The length of a rectangular field is 8 meters less than twice its breadth.
• The perimeter of the rectangular field is 56 m.

To Find :-

• The length and breadth of rectangular field.

Step-by-Step-Explaination :-

Let,

• The breadth of the rectangular field be x

• The length of the rectangular field be 2x - 8

According to the condition,

As we know that :-

Perimeter of rectangle = 2 ( l + b )

Where,

• Perimeter of rectangle = 56 cm

• l = 2x - 8

• b = x

Putting the respective value,

56 = 2 ( 2x - 8 + x )

56/2 = 2x - 8 + x

28 = 3x - 8

28 + 8 = 3x

36 = 3x

x = 36/3

x = 12

Thus,

The breadth of rectangle = x = 12 m

The length of rectangle = 2x - 8 = 24 - 8 = 16 m

Hence Solved !