The length of a rectangular field is 8,mt less than twice it's breadth .If the perimeter of the rectangular field is 56mt, find its length and breadth?
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Hi there,
Make the width = 'x'
Length = 3x - 8
Area = length x width
35 = (3x - 8) * x (* = times)
35 = 3x^2 - 8x
Rearrange into quadratic = 0
3x^2 - 8x - 35 = 0
(3x + 7)(x - 5) = 0
3x + 7 = 0
x = -7/3 (ignore as -ve)
x - 5 = 0
x = 5
Width = 5 ft
Length = 7 feet
Hope this helps :-)
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