the length of a rectangular field is 8M.
less than twice its breadth of the peremeter
of the rectangle field is 56, find
length and breadth ?
Answers
Answered by
0
Answer:
length= 18
breadth = 10
Step-by-step explanation:
x = 2y-8
2(x + y) = 56
x+y= 56/2= 28
if y= 10 then x = 18 ( 10*2 =20 and 20- 2 =18)
10 + 18= 28
therefore length= 18
breadth = 10
Answered by
0
ᴘᴇʀɪᴍᴇᴛᴇʀ ᴏғ ʀᴇᴄᴛᴀɴɢʟᴇ = 56 ᴍ
Solution:-
⇒ 2(l+b)=56
⇒ 2(2x−8+x)=56
⇒ 3x−8=28
⇒ 3x =28+8
⇒ x=36/3=12m
Therefore :-
ʟᴇɴɢᴛʜ(ʟ) = 2x-8 =2×12 - 8 =16 ᴍᴇᴛᴇʀs.
ʙʀᴇᴀᴅᴛʜ(ʙ) = x = 12 ᴍᴇᴛᴇʀs.
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