Question

the length of a rectangular field is 8meters less than twice its breadth.If the perimeter of a rectangular field is 56meters. Find its length and breadth
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Answer 1

Answer:

Given, l= 2b-8

P= 56m.

Formula, P= 2(l+b)

Or, 56 = 2(2b-8+b)

Or, 56= 2(3b-8)

Or, 3b-8 = 56/2

Or, 3b-8 = 28

Or, 3b = 28+8

Or, 3b= 36

Or, b = 36/3 = 12 m

Now, l=2b-8

= 2×12-8

= 24-8 =16 m

Thus, l = 16 m and b = 12 m.

Answer 2

Answer:

23

Step-by-step explanation:

Let the breadth of the triangle = x meters.

Let the lenght of Rectangle = (x+8)

L = (x+8)

B = x

Perimetre of Rectangle = 2(L+B)

2( x+8+x )

According to the problem

Perimetre = 108 meters

4x = 108 - 16

4x  = 12

x     = 92/4.

x       = 23.

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