Question

the length of a rectangular field is 8metres less than twice it's breadth . if the perimeter of the rectangular field is 56 metres, find its length and breadth​

Answer 1

Answer:

length of rectangle = 16 m

breadth of rectangle = 12m

Step-by-step explanation:

let the breadth of rectangular field = x

and it's length = 2x - 8

perimeter of rectangle = 2(l + b)

56 = 2(2x - 8 + x)

56 = 2(3x - 8)

56 = 6x - 16

56 + 16 = 6x

72 = 6x

72/6 = x

12 = x

breadth of rectangle = x = 12 m

and it's length = 2x - 8

2 × 12 - 8

24 - 8 = 16 m

Answer 2

Answer :-

$\bf\huge\boxed{l - 16 m ; b - 12 m}$

Explanation :-

Given :

• Length of the rectangular field - 8 metre less than twice it's breadth
• Perimeter of the rectangular field - 56 m

To find :

The length and breadth of the rectangular field

Solution :

Let the Breadth of the field be = x m

and the Length = (2x - 8) m

We know that,

Perimeter = 2(length + breadth)

=> Perimeter = 56 m

=> 2 {x + (2x - 8)} = 56

=> 2 {x + 2x - 8} = 56

=> 2 {3x - 8} = 56

=> 6x - 16 = 56

=> 6x = 56 + 16

=> 6x = 72

=> x = 72/6

=> x = 12

Therefore, the value of x is 12

Now,

The breadth => x = 12 m

The length => 2x - 8 = 2 × 12 - 8 = 24 - 8 = 16 m

Hence, The length and breadth of the rectangular field is 16 m and 12 m respectively.